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x^2-8x-16.25=0
a = 1; b = -8; c = -16.25;
Δ = b2-4ac
Δ = -82-4·1·(-16.25)
Δ = 129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-\sqrt{129}}{2*1}=\frac{8-\sqrt{129}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+\sqrt{129}}{2*1}=\frac{8+\sqrt{129}}{2} $
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